针对网友菜鸟的问题，制作了本示例

(1)如何判断表Sheet1的字段IOTime的时间如果>17:45:00就在17：25：00 与17:45:00之间随时取数更新（2）如果同一天，同一个人的字段IOTime时间>17：25：00有多条记录，就删除多余的，只保留一条记录（因为数据较多，有没有方法做到以后功能，执行速度又快呢:)）

表Sheet1 的副本保存的是未处理前数据。

代码：

Private Sub Command0_Click()
Dim sql As String, sj(1) As String
sj(0) = "17:25:00"
sj(1) = "17:45:00"
DoCmd.DeleteObject acTable, "aa"

sql = "Select Sheet1.DepartmentName, Sheet1.HolderNo, Sheet1.CardNo, Sheet1.HolderName, Sheet1.IODate, Min(Sheet1.IOTime) AS aa INTO aa "
sql = sql & "FROM Sheet1 "
sql = sql & "Where IOTime > '" & sj(0) & "' And IOTime< '" & sj(1) & "' "
sql = sql & "GROUP BY Sheet1.DepartmentName, Sheet1.HolderNo, Sheet1.CardNo, Sheet1.HolderName, Sheet1.IODate;"
CurrentDb.Execute sql

sql = "Delete Sheet1.*, Sheet1.IOTime "
sql = sql & "FROM Sheet1 "
sql = sql & "Where IOTime > '" & sj(0) & "' And IOTime< '" & sj(1) & "';"
CurrentDb.Execute sql

sql = "Insert INTO Sheet1 ( DepartmentName, HolderNo, CardNo, HolderName, IODate, IOTime ) "
sql = sql & "Select aa.DepartmentName, aa.HolderNo, aa.CardNo, aa.HolderName, aa.IODate, aa.aa "
sql = sql & "FROM aa;"
CurrentDb.Execute sql

DoCmd.DeleteObject acTable, "aa"

End Sub

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